Basic Electrical Engineering - Electrical Engineering (MCQ) questions and answers for Q. 9006

Q.  If a current of 5A flows through a resistor of 12 ohm then the power developed and the energy dissipated in 2 minutes are
- Published on 02 Sep 15

a. 300 W, 36000 J
b. 360 W, 30000 J
c. 380 W, 35000 J
d. 380 W, 36000 J

ANSWER: 300 W, 36000 J

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    Discussion

  • Nilanjan Hatua   -Posted on 28 Sep 23
    Current(I) = 5A
    Resistance(r) = 12 ohm
    so, Voltage(V) = I x r = 5 x 12 = 60 Volt
    Power(p) = V x I = 60 x 5 = 300 watt ..........(i)

    so, Time(t) = 2 min = 60 x 2 sec = 120 sec.
    Energy dissipation = power x time
    = 300 x 120
    =36,000 j ............(ii)
  • Sutikshan Vohra   -Posted on 06 Mar 21
    ok

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