Calculation of Modulation index and Maximum frequency deviation in FM wave

Q.  For a FM signal v(t) = 25 cos (15 * 108t + 10 sin 1550t), calculate
Modulation index
Maximum frequency deviation

- Published on 14 Oct 15

a. 10, 3000.1Hz
b. 20, 1550.9Hz
c. 10, 2465.9Hz
d. 10, 2000.0Hz

ANSWER: 10, 2465.9Hz
 
Standard expression for FM signal is given by
v(t) = A cos ( ωct + mf sin ωmt)
Comparing with the given equation,
Modulation index mf = 10
Maximum frequency deviation is given by
mf = Δf/fm
Δf = mf * fm
Here fm = 1550/2Π = 246.59 Hz
Δf = 10 * 246.59
= 2465.9Hz
 

    Discussion

  • Michael Awuley Lartey    -Posted on 30 Oct 16
    Want to join for solution to some questions

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