Prepare
Practice
Interview
Aptitude
Reasoning
English
GD
Placement papers
HR
Current affairs
Engineering
MCA
MBA
Online test
Login
Center of gravity - Isosceles triangle
Home
>>
Category
>>
Mechanical Engineering (MCQ) questions and answers
>>
Engineering Mechanics
Q. What is the C.G of an isosceles triangle of base 20 cm and side 40?
- Published on 18 Sep 15
a.
12.90 cm
b.
13.28 cm
c.
19.36 cm
d.
38.72 cm
ANSWER: 12.90 cm
Related Content
Fluid Mechanics (
75
)
Manufacturing Processes - 1 (
75
)
Manufacturing Processes - 2 (
65
)
Material Science (
70
)
Theory of Machines - 1 (
60
)
Metrology and Quality Control (
151
)
Theory of Machines - 2 (
75
)
Heat Transfer (
271
)
Hydraulics & Pneumatics (
228
)
Thermodynamics (
388
)
Basic Mechanical Engineering (
91
)
Dynamics of Machinery (
92
)
Engineering Metallurgy (
61
)
Design of Machine Elements - 1 (
81
)
Mechatronics (
60
)
Turbo Machines (
70
)
Mechanical System Design (
73
)
Engineering Mechanics (
103
)
Strength of Materials (
110
)
Design of Machine Elements - 2 (
69
)
Discussion
Punit kumar singh
-Posted on 14 Oct 19
Feom where base, ya top if we take from base then it will right but if u take from top it will be 2h/3
Sravanthi
-Posted on 14 Dec 15
Given:
Base of an isosceles triangle = 20 cm, side = 40 cm
Formula:
Centroid = Height of isosceles triangle (h) / 3
Solution:
- O is the centroid of triangle PQR.
- Height of triangle = √(40)
2
- (10)
2
= 38.72 cm
Centroid of triangle along y – axis = h / 3
= 38.72 / 3
= 12.90 cm
➨
Post your comment / Share knowledge
Required!
Required!
Invalid Email Id!
Required!
Enter the code shown above:
Please enter the code shown above
(Note: If you cannot read the numbers in the above image, reload the page to generate a new one.)
MCQs
English
Tutorials
Download
▲