Communication System - GATE practice papers - Electronics & Communication for Q. 541

Q.  Which conditions justify the mutual orthogonality of two random signals X(t) & Y(t)?
(Marks : 02)
- Published on 19 Oct 15

a. RXY , (t1, t2 ) = 0 for every t1 and t2
b. RXY , (t1, t2 ) = 1 for every t1 and t2
c. RXY = 0, (t1, t2 ) = 1 for t1 and t2 instants respectively
d. RXY = 1 , (t1, t2 ) = 0 for t1 and t2 instants respectively

ANSWER: RXY , (t1, t2 ) = 0 for every t1 and t2
 
Two random X(t) & Y(t) processes are usually said to be mutually orthogonal only and only if RXY, (t1,t2) becomes exactly equal to zero; where
t1 & t2 are the two time instants at which the processes are observed.

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