Fraction - Quantitative Aptitude (MCQ) questions for Q. 21063

Q.  The product of two fractions is 3/4 and their quotient is 6/18. If the denominator of one is 1/3 of the other's numerator, then find the pair of fractions?
- Published on 19 Apr 16

a. 1/3, 9/5
b. 1/2, 3/2
c. 1/2, 6/5
d. Data inadequate
e. None of these

ANSWER: 1/2, 3/2
 
Let A = x/y, and B be two fractions
It is given that A*B = 3/4
Therefore x/y * B = 3/4
B = 3y/4x
Therefore, A = x/y and B = 3y/4x
It is given that A/B = (x/y) / (3y/4x) = 6/18
Therefore x/y * 4x/3y = 6 /18
Therefore 4x2/3y2 = 6/18
x2/y2 = 18/(4*18)
Therefore, x2/y2 = ΒΌ
x/y = 1/2
B = 3y/4x = 3/4 (1/(x/y)) = 3/4 [1/(1/2)] = 6/4
Therefore A = 1/2 and B = 3/2

Related Content

➨ Post your comment / Share knowledge


Enter the code shown above:

(Note: If you cannot read the numbers in the above image, reload the page to generate a new one.)
▲