Frequency deviation calculation from FM equation

Q.  Calculate the maximum frequency deviation for the FM signal
v(t) = 10 cos (6000t+ 5sin2200t)
- Published on 14 Oct 15

a. 2200 Hz
b. 6000 Hz
c. 1750 Hz
d. 11000 Hz

ANSWER: 1750 Hz
 
A standard FM signal is represented by
v(t) = Ac cos(2πfct + kfsin2πfmt)
Ac = carrier amplitude
fc = carrier frequency
kf = modulation index
fm = modulating frequency = 2200/2π = 350 Hz
kf = frequency deviation/modulating frequency
5 = freq deviation/ 350
Therefore, deviation = 5 * 350
= 1750Hz

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