Numerical -Peak restriking voltage for given distributed capacitance of 3-phase alternator

Q.  Refer to the following facts to answer the question

A 50 Hz, 11 kV, 3 phase alternator with earthed neutral having a reactance of 3 ohms per phase and is connected to a bus bar through a circuit breaker, if the distributed capacitance upto CB between the phase and neutral is 0.01 μ F.

What is the peak re striking voltage?
- Published on 17 Nov 15

a. 18.36 kV
b. 17.96 kV
c. 15.96 kV
d. 12.65 kV

ANSWER: 17.96 kV

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    Discussion

  • KHANDEKAR MANISH JAGDISH   -Posted on 21 Sep 23
    Max value of restriking voltage = 2 * Epeak
    RMS value of pH voltage=11/v3= 6.35
    E peak = v2*6.35= 8.98
    Max value of restriking volage= 2*8.98 = 17.96
  • Deepraj   -Posted on 06 Aug 23
    The peak re striking voltage is given by:
    V = v3 * line voltage * reactance * capacitance
    In this case, the line voltage is 11 kV, the reactance is 3 ohms, and the capacitance is 0.01 µF. Plugging these values in, we get:
    V = v3 * 11 kV * 3 ohms * 0.01 µF
    = 17.96 kV


    So the correct answer is b.
  • Parash chaudhary   -Posted on 11 May 22
    I want to see ans

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