Numerical - Rectangular tapered plate, given width, load

Q.  In the diagram shown below, a tensile load of 50 kN is applied axially. What is the increase in length of the rectangular tapered plate of width 10 mm. (Assume E = 220 Gpa)
- Published on 21 Sep 15
Numerical-Rectangular-tapered-plate.png


a. 0.10 mm
b. 0.161 mm
c. 0.126 mm
d. 0.56 mm

ANSWER: 0.126 mm

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    Discussion

  • Sravanthi   -Posted on 24 Nov 15
    Given: Tensile load = 50 kN, width of tapered plate = 10 mm, d1 = 100 mm, d2 = 50 mm, force (P) = 50 x 103 N, E = 220 x 103 MPa

    Formula: δL = [(PL) / (d1- d2 ) w E] [loge (d1/d2)]

    δL = increase in length,


    Substituting the given values,

    δL = [(50 x 103 x 400) / (100 - 50 ) 10 x 220 x 103] [loge (100/50)]

    = 0.126 mm

    Increase in length of the rectangular tapered plate of width 10 mm = 0.126 mm

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