Numerical - Shear stress, given force & square

Q.  A square object of 4 mm is subjected to a force of 3000 N. What is the maximum allowable shear stress acting on it?
- Published on 21 Sep 15

a. 250.14 mm2
b. 281.25 mm2
c. 400.32 mm2
d. 500 mm2

ANSWER: 281.25 mm2

Related Content

 

    Discussion

  • Sravanthi   -Posted on 24 Nov 15
    Given: side of square = 4 mm, force = 3000 N

    Formula: Maximum allowable shear stress (τmax) = (3/2) (τavg)

    Solution:

    (τmax) = (3/2) (τavg) = (3/2) (F/A)

    = [3/2] x [3000/(4)2]

    = 281.25 mm2

    The maximum allowable shear stress is 281.25 mm2

➨ Post your comment / Share knowledge


Enter the code shown above:

(Note: If you cannot read the numbers in the above image, reload the page to generate a new one.)
▲