Permutations and combinations - Quantitative Aptitude (MCQ) questions for Q. 119

Q.  In a group containing 6 cows and 4 buffalos, 4 livestock are to be selected in such a way that at least 1 cow should always be present. How many way of doing that are possible?
- Published on 15 Jun 15

a. 209
b. 205
c. 194
d. 163

ANSWER: 209

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    Discussion

  • Mahalakshmi S   -Posted on 03 Jul 24
    6C1*4C3+6C2*4C2+6C3*4C1+6C4*4C0=209
  • Madhuri    -Posted on 20 May 20
    Total ways to select 4 live stock =10C4=210
    All non cow selections = 4C4 =1

    At least 1 cow selections = Total ways of selections- All non cow selections =210-1=209

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