Problem on Ages - Quantitative Aptitude (MCQ) questions for Q. 20987

Q.  15 years ago, a father was three times as old as his daughter. Now the father is only twice as old as his daughter. Find the sum of the present ages of daughter and father.
- Published on 15 Apr 16

a. 54
b. 65
c. 90
d. 108

ANSWER: 90
 
The present age of father and daughter be 2x and x years respectively.
Then, (2x - 15) = 3 (x – 15)
2x – 15 = 3x - 45
x = 30
Required sum = (2x + x) = 3x = 90 years.

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