Problems on Numbers - Quantitative Aptitude (MCQ) questions for Q. 49

Q.  A natural number is greater than another natural number by 3. The sum of their squares is 89. Find them.
- Published on 12 Jun 15

a. 5, 8
b. 11, 8
c. 4, 7
d. 9, 6

ANSWER: 5, 8
 

    Discussion

  • Divya Sahu   -Posted on 12 Jan 20
    Let N1 and N2 are two natural numbers
    N1 is greater than N2 by 3 i.e.
    N1 - N2 = 3 …... (1)

    Sum of squares of N1 and N2 is 89 i.e.
    N1^2 + N2^2 = 89

    (N1 - N2)^2 = 3^2
    N1^2 + N2^2 - 2N1N2 = 9
    89 - 2N1N2 = 9
    2N1N2 = 89 - 9
    N1N2 = 80/2 = 40
    LCM of 40 = 2*2*2*5
    (N1,N2) = (2*2*2,5) = (8,5) or (5,8)

Post your comment / Share knowledge


Enter the code shown above:

(Note: If you cannot read the numbers in the above image, reload the page to generate a new one.)