Projectile motion of ball thrown at an angle

Q.  Assume that same ball is thrown at two angles 50o and 80o from the ground with initial velocity of 12 m/s.
(1) At which angle ball covers the maximum distance?
(2) What is the maximum distance covered by the ball?
- Published on 18 Sep 15
Projectile-motion.png


a. 50o, 14.45 m
b. 50o, 11.24 m
c. 80o, 50.33 m
d. 80o, 16.26 m

ANSWER: 50o, 14.45 m

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    Discussion

  • Kumaravel   -Posted on 29 Aug 17
    why cant we use .....2usin(alpha)/g formula???
  • mzainulabedin   -Posted on 07 Jun 17
    great work
  • Sravanthi   -Posted on 15 Dec 15
    Given: α = 80°, α = 50°, initial velocity = 12 m/s

    Solution:

    When α = 80°, u is the initial velocity = 12 m/s

    Distance covered = (u2 sin 2α) / g

    Substituting the given values,

    = (122 sin 2 x 80) / 9.810

    = 5.02 m

    When α = 50°,

    = (122 sin 2 x 50) / 9.81

    = 14.45 m

    The maximum distance covered is 14.45 m when α = 50°

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