Simply supported beam - Reactions at end points

Q.  Uniformly distributed load of 5 kN acts on a simply supported beam of length 10 m. What are the reactions at end points of the beam?
- Published on 18 Sep 15

a. 12.5 kN
b. 25 kN
c. 50 kN
d. None of the above

ANSWER: 25 kN

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    Discussion

  • Sravanthi   -Posted on 14 Dec 15


    - Uniformly distributed load of 5 kN acts on a simply supported beam of length 10 m as shown above.

    Given: Uniformly distributed load = 5 kN, length of beam = 10 m

    Solution:

    Reactions at point P and Q are same due to symmetrical loading.

    Reaction at point P (Rp) = Reactions at point Q (RQ)

    Therefore,

    (Rp) = (RQ) = (Total downward force acting on beam PQ) / 2

    = (5 x 10) / 2

    = 25 kN

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