Strength of Materials - GATE practice papers - Mechanical for Q. 355

Q.  A spring of radius 1 cm obeys Hooke's law. A mass of 2 kg is attached to the spring. Calculate the extension of the spring. The spring constant k is 110 N/m
- Published on 19 Oct 15

a. 17.81 m
b. 0.1781 cm
c. 0.1781 m
d. 0.1781 mm

ANSWER: 0.1781 m
 
According to the Hooke's law force applied to extend or compress a spring is directly proportional to change in length of the spring. Therefore F = – kX where k is spring constant. By using this formula and taking force applied F = mg = 2 × 9.8 =19.6 N and k = 110 N/m we can fine X.

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