What is the expression for mechanical power developed in terms of load angle & internal machine angle for constant voltage & constant excitation?

Q.  The expression for the mechanical power developed in terms of the load angle δ and the internal machine angle ∅, for constant voltageVph and constant excitation Eb is
- Published on 29 Oct 15

a. [{(EbVph) / Zs} * cos(θ - δ)] - [{(E2b) / Zs} * cos θ]
b. [{(EbV ph) / Zs} * cos(δ - θ)] - [{(E2b) / Zs}* cos θ]
c. [{(E2b) / Zs} * cos θ] - [{(Eb Vph) / Zs} * cos(δ - θ)]
d. [{(E2b) / Zs} * cos θ] - [({Eb Vph) / Zs} * cos(θ - δ)]

ANSWER: [{(EbVph) / Zs} * cos(θ - δ)] - [{(E2b) / Zs} * cos θ]

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