Two pipes X and Y can fill a tank in 50 hours and 60 hours respectively. If both the pipes open together for 10 hours, then Y is closed. In how much time X fill the remaining tank?

Options
- 19 hours
- 28 hours
- 38 hours
- 30 hours

CORRECT ANSWER : 38 hours

Discussion Board
Answer

Calculate the rates at which the pipes fill the tank:

Pipe X can fill the tank in 50 hours. Therefore, its rate is
1
50
50
1
?
of the tank per hour.
Pipe Y can fill the tank in 60 hours. Therefore, its rate is
1
60
60
1
?
of the tank per hour.
Calculate the combined rate of pipes X and Y:

Combined rate of X and Y
=
1
50
+
1
60
Combined rate of X and Y=
50
1
?
+
60
1
?

To add these, we need a common denominator:

1
50
=
6
300
and
1
60
=
5
300
50
1
?
=
300
6
?
and
60
1
?
=
300
5
?

So,

1
50
+
1
60
=
6
300
+
5
300
=
11
300
50
1
?
+
60
1
?
=
300
6
?
+
300
5
?
=
300
11
?

Therefore, pipes X and Y together fill
11
300
300
11
?
of the tank per hour.

Calculate the amount of the tank filled in the first 10 hours:

Amount filled in 10 hours
=
10
×
11
300
=
110
300
=
11
30
Amount filled in 10 hours=10×
300
11
?
=
300
110
?
=
30
11
?

So,
11
30
30
11
?
of the tank is filled in the first 10 hours.

Calculate the remaining amount of the tank to be filled after the first 10 hours:

Remaining amount to be filled
=
1
-
11
30
=
30
30
-
11
30
=
19
30
Remaining amount to be filled=1-
30
11
?
=
30
30
?
-
30
11
?
=
30
19
?

Calculate the time required for pipe X to fill the remaining
19
30
30
19
?
of the tank:

Since pipe X''s rate is
1
50
50
1
?
of the tank per hour:

Time required
=
Remaining amount
Rate of X
=
19
30
1
50
=
19
30
×
50
=
950
30
=
31
2
3
 hours
=
31.67
 hours
Time required=
Rate of X
Remaining amount
?
=
50
1
?

30
19
?

?
=
30
19
?
×50=
30
950
?
=31
3
2
?
 hours=31.67 hours

Maan 07-26-2024 09:18 PM

solution of above problem

plz provide me the sol.

jaspreet kaur 12-26-2019 08:59 PM

wrong answers

most of the answers u have provided are wrong answers

sakshi 11-29-2019 03:06 PM

wrong options

solution plzz

Anjali garg 09-23-2018 04:51 AM

sir can u give me the solution of this problems plz

sir can u give me the solution of this problems plz

trinadh 02-6-2015 12:51 AM

Write your comments


Enter the code shown above:

(Note: If you cannot read the numbers in the above image, reload the page to generate a new one.)


Advertisement
 
▲