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consider units digit 3+9(3^2)+7(3^3)+1(3^4) = 20- 1st 4 terms similarly, the next 4 terms are also 20 then only 2 terms remain, i.e unit digits of (3^9)+(3^10)=3+9=12 so 2 is the unit digit of the entire sum teja 07-1-2024 04:22 AM

Maths By using x(r^n-1) /r-1 3(3^10-1) /(3-1) =88572 P vishnu teja 08-21-2021 08:00 AM

Solution to above problem Anyone plzz provide the steps to calculate this problem Madhav 06-25-2018 07:41 AM

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