What is the remainder when 12+122+123……+129 is divided by 9?

Options
- 3
- 6
- 9
- 0

CORRECT ANSWER : 0

Discussion Board
apptitude

take the 12 as common from all the number and we get 12(1+1^2+1^3.....1^9)
12(1+1+1...1)=12(9)/9== remainder is 0

POthamsetty venkatesh 08-2-2021 10:26 AM

Answer is wrong

Correct answer is 3
Because
Except 12 all other are perfectly divisibe by 9 (as it contains 3 atleast 2 times in pr faction)

Tarun 08-23-2020 06:52 AM

attitude

i need this one

reddy 03-15-2016 02:28 PM

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