What could be the maximum value of B in the following equation?

2A8 + 3B5 + 5C8 = 1111

Options
- 3
- 5
- 9
- 0

CORRECT ANSWER : 9

Discussion Board
Method

we are given that,

2A8 + 3B5 +5C8 = 1111

Let us solve by following method :

(200 + A0 + 8) + (300 + B0 + 5) + (500 + C0 + 8)=1111

After adding all 100 and one''s unit we get,

(1000+21) + (A+B+C)10=1111

Taking the total 1021 on another side,
(A+B+C)10 = 1111-1021 ,we will get 90
then dividing 90 / 10 = 9

Thus max value i.e 9 will be given to B, whereas A =0, C=0

208 +395+508 =1111

Nandini 06-16-2019 11:09 AM

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I want solution

Roshan sharma 10-8-2018 12:52 PM

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