A group of sweepers sweep the floor of auditorium in 10 days but out of them 5 could not join the team. If the rest of sweepers sweep the floor in 12 days, the number of sweepers present originally in the team was. (Assuming all the sweepers have equal efficiency)

Options
- 30
- 45
- 50
- 35

CORRECT ANSWER : 30

Discussion Board
xyz

''x'' member of sweepers complete the work in 10days
therefore
x=>10days=>1 work
1 day work=1/10x
five member dont join
x-5=>12 days=>1 work,
therefore
1/12(x-5)
since efficiency is same
1/10x=1/12(x-5)
solving this we get
x as 30

tulajaram 01-4-2019 02:51 AM

how to solve the problem

what''s the approach for this problem?plz help

sdv 08-30-2018 06:53 AM

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