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Number 2
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What is the remainder when (1! + 2! + 3! + … + 50!) is divided by 7?
Options
- 1
- 3
- 5
- cannot be determined
CORRECT ANSWER : 5
Discussion Board
Problems on Number
Soln: - As the division is by 7, numbers 7! onwards are eliminated as they are completely divisible by 7.
Therefore, we need to find the remainder when (1!+2!+3!+4!+5!+6!) is divided by 7.
(1!+2!+3!+4!+5!+6!) = (1+2+6+24+120+720) = 873
On division of 873 by 7, the remainder is 5.
Problems on Number 07-26-2013 08:10 AM
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